Date   : Tue, 08 Sep 2009 19:08:11 +0100
From   : info@... (Sprow)
Subject: Leccy @ Acorn World '09

In article <4AA61050.5000507@...>,
   Mick Champion <rs423@...> wrote:
> Sprow wrote:
> >
> > It's linear with length, so half the length is half the resistance etc...
> > Therefore a socket which was closer to the fuse box might be served by a
> > short cable of 0.5 ohms, and a much longer one of 1.5 ohms for example 
> > (such
> > that they add up to 2 ohms again).
> >
> > Then the resistance would be
> >
> >  [ (1/1.5) + (1/0.5) ] ^-1
> >
> > which is 0.375 ohms: better!
> >
> > I chose the centre point of the ring because that's the worst case,
> >   
> Oh I see... I think? So as you move clockwise or anti-clockwise frim the 
> centre of the loop, the resistance will increase on one cable, and 
> decrease on the other cable giving overall the same resistance where 
> ever you may be. Is that it? 

Correct. Resistance is at a minima next to the consumer unit, increases to a
maxima at the middle of the ring, then decreases again towards the consumer
unit,
Sprow.